Given an integer value input,determine if that value is even or odd?

write in pseudocode solution

void checkNumber(int number)
{
if(number is divisible by 2)
print "The number is even";
else
print "The number is odd";
}

public boolean isEven(int input)
{
return (input MOD 2) ;
}

Pseudocode?!?! you sure.... well ok

GET input integer
CALCULATE if input integer is even
DISPLAY result

If you want actual logic Pseudocode does not dabble with specifics but rather data flow... for logical answer Ashok has given you the solution... Mod the integer by 2. if it returns 0 its even if it returns 1 its odd.

10 INPUT NUMBER
20 REMAINDER = NUMBER MOD 2
30 IF REMAINDER < .1 THEN PRINT "Number - Even" ELSE PRINT "Number = Odd"
Hope this helps...

boolean IsEven(integer value){
return ((value mod 2) = 0);
}

boolean IsOdd(integer value){
return (value mod 2);
}

"mod" is a pretty common operator in many programming languages... it returns the modulus--the remainder.

Likewise, in most languages, 0 will convert to False, and 1 will convert to True when setting or returning a boolean value.

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