How do you solve the following problem recursively?

I was wondering how to solve the following problem:

Write a Java method 'printAlternateDigits' that takes an integer as a parameter and prints every alternate digit, ending at the rightmost digit. No credit will be given for non-recursive implementation. No copying to arrays or strings is allowed.

Example Input and Output:
45452 returns 442
643634 returns 4
456 returns 46
67 returns 7
7 returns 7

So? Any ideas. Here's how I had started it out earlier:

public static void printAlternateDigits (int num)
{
// Base Case
if ((int)(num/100)==0)
System.out.println(num - (int)(num/10)*10);
// Recursion
else
printAlternateDigits(umm...wtf? I'm lost!!);
}

Please help me out. This actually isn't an assignment. It was a test question that I had yesterday and it screwed me over, and I'm pissed. I think this problem was too hard for the first exam.

Anyway, thanks for your help guys!

I'm not familiar with Java functions (you need mod and a print statement that doesn't add a newline) . Formatting is probably a little screwed up...want it in python?

public static void printAlternateDigits( int num)
{
if num>0
{
myPart = num % 100 // or is it mod(num,100)
printAlternateDigits( (num-myPart)/100 )
System.out.println(myPart %10)
}
}

by mod I mean:

12345 % 100 = 45

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